Expression for height of water as a function of time given flow rate in and out

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SUMMARY

The discussion focuses on deriving an algebraic expression for the height of water in a wedge-shaped trough as a function of time, given the volumetric flow rates of water entering (Qi) and exiting (Qj). The approach begins with a mass flow rate balance, represented by the equation dm/dt = (Qi - Qj)p, where p denotes the density of the liquid. The user suggests exploring the relationship between flow rates and volume changes over time, leading to the equation (Qi - Qj)t = volume in trough, and proposes using the derivative of height with respect to volume to find dH/dt.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically mass flow rate.
  • Familiarity with calculus, particularly derivatives and their application in volume changes.
  • Knowledge of geometric properties of wedge-shaped volumes.
  • Basic understanding of density and its role in fluid mechanics.
NEXT STEPS
  • Explore the derivation of the volume of a wedge-shaped trough.
  • Study the application of the continuity equation in fluid dynamics.
  • Learn about the relationship between flow rates and height changes in open channel flow.
  • Investigate the use of differential equations to model fluid height changes over time.
USEFUL FOR

Students in fluid mechanics, engineers working with fluid systems, and anyone involved in modeling water flow in geometric containers.

rewrew
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Homework Statement



Consider the filling of a horizontal wedge-shape trough of height H, length, L, and width, B with water. (Imagine a water trough for horses with ends that are matching triangles). The volumetric flow rate of water in is given by Qi and the flow rate out by Qj. Obtain an algebraic expression for the change in height of the water in the trough as a function of time.


Homework Equations



no idea, open ended question

The Attempt at a Solution




I tried starting with a mass flow rate balance:

dm/dt = p dA/dt v = (Qi-Qj)p

p=density of liquid
v=velocity
A=area

But then I thought maybe I should try doing something with volume?
(Qi-Qj)t= volume in trough
 
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[tex]\frac{dH}{dt} = \frac{dH}{dV} \frac{dV}{dt}[/tex]

Start with this perhaps
 

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