Expression for orbital eccentricity

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SUMMARY

The discussion focuses on deriving an expression for orbital eccentricity (e) based on initial speed (v), radius (r), and flight path angle (x) as outlined in Prussing and Conway's problem Q1.11. Key equations include the specific angular momentum equation (h^2 = mu*a*(1-e^2)), the relationship between angular momentum and radius (h = r*v*cos(x)), and the velocity equation (v^2 = mu*((2/r)-(1/a))). The derived expression for eccentricity involves complex rearrangements, ultimately leading to e^2 = 1 - [(r^2*v^2*cos^2(x)) / mu]*[(2/r)-(v^2/mu)], which is acknowledged as unwieldy but necessary for the problem.

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  • Understanding of orbital mechanics and eccentricity
  • Familiarity with gravitational parameters (mu)
  • Knowledge of angular momentum in orbital dynamics
  • Ability to manipulate algebraic expressions involving trigonometric functions
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Robaj
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Homework Statement



From Prussing and Conway (Q1.11): derive an expression for the eccentricity e in terms of the initial speed v, radius r, and flight path angle x (they use gamma).

Homework Equations



(1) h^2 = mu*a*(1-e^2) [a is semimajor axis, mu is gravitational parameter]
(2) h = r*v*cos(x)
(3) v^2 = mu*((2/r)-(1/a))

The Attempt at a Solution



Rearrange (1): a = h^2/(mu*(1-e^2))

Sub in (2): a = (r^2*v^2*cos^2(x)) / (mu*(1-e^2))

Rearrange for e: e^2 = 1-[(r^2*v^2*cos^2(x)) / (mu*a)]

Rearrange (3) in terms of a and sub in: e^2 = 1-[(r^2*v^2*cos^2(x)) / mu]*[(2/r)-(v^2/mu)]

This seems far too unwieldy.. have I misunderstood the basic geometry or relationships behind the problem? I've been unable to find an expression for e = f(r,v,x) anywhere .

Thanks for your help.
 
Last edited:
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I don't think it can be made significantly simpler if it has to be expressed as a function of r, v, and γ. At least one of my textbooks has a similar unruly expression for e (although it uses a instead of v).
 
Ok, I'll leave it as it is. Thanks a lot.
 

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