Expression for time period of simple pendulum

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SUMMARY

The discussion centers on the expressions for the time period of a simple pendulum, specifically comparing t = 2π√(l/g) and t = 2π√(1/T/m). The consensus is that the first expression, t = 2π√(l/g), is the more accurate representation of the time period, where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity. The second expression is deemed less useful due to the misinterpretation of forces involved, particularly the distinction between gravitational force and pseudo centrifugal force.

PREREQUISITES
  • Understanding of basic physics concepts, particularly mechanics.
  • Familiarity with the principles of pendulum motion.
  • Knowledge of gravitational acceleration (g) and its implications.
  • Basic mathematical skills for manipulating square roots and equations.
NEXT STEPS
  • Study the derivation of the formula for the time period of a simple pendulum.
  • Explore the effects of varying mass on the pendulum's motion.
  • Investigate the impact of air resistance on pendulum dynamics.
  • Learn about advanced pendulum systems, such as compound pendulums.
USEFUL FOR

Physics students, educators, and anyone interested in classical mechanics and pendulum dynamics will benefit from this discussion.

anigeo
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Which of the two is a better expression for the time period of a simple pendulum?
t-=2∏[itex]\sqrt{(l/g)}[/itex] or t=2∏[itex]\sqrt{(1/T/m)}[/itex] ; l=length of the pendulum
T=time period of the pendulum
m=mass of bob
Note:g is not equal to T/m as there is pseudo centrifugal force such that T + centripetal force=mg
 
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The first one is the useful expression...
 

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