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vincentchan
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What is exterior product?
vincentchan said:What is exterior product?
vincentchan said:I know its definition, my question is why is it define this way, ie. v^w=-w^v and v^v = 0
vincentchan said:May I moldify my question the other way, What is exterior product use for and when will we use it (for a real physical application)?
dextercioby said:General Relativity can be taught without geometrical description.
Geometric quantization can be taught only if you're taught classical dynamics and symplectic manifolds,like "phase-space".
Thermodynamics can be taught without making too much mathematical analysis of the differential forms like differential heat and differential work.
marlon said:Interesting, yet hard to believe...how is this done...please enlighten us...
marlon said:mmm, it's a little bit more then that...Besides it is even better if you do not have any notion on the way classical dynamics work because it must be easier to not get confused...But your list is faaaaaaaaaaar from complete that it is wrong. Also incluse GTR + QFT Thus also QM and special relativity...Ever saw a paper on LQG, check out my journal and you shall be convinced ?
marlon said:Then how ? No partition functions, no total differentials (how are you going to incorporate reversal processes and therefore hysteresis?) ? What part of thermodynamics are you planning on teaching ?
marlon said:CONCLUSION : i am glad not to be a student of yours
marlon
dextercioby said:I wrote there.I was referring to the course of Mr.Dirac.Why didn't u read all the way??Complete reading sometimes "enlightens"... :tongue2:
I certainly didn't...Who said i was making a complete list??Marlon don't read too much into it...
Ever heard of the two formulations of classical reversible processes thermodynamics??
Guess not,if u did,u know i was referrng to the neogibbsian formulation...
Too bad u'll never be one of my students...You could learn so many...
vincentchan said:I know its definition, my question is why is it define this way, ie. v^w=-w^v and v^v = 0
marlon said:No no, that is avoiding an answer...Please explain how this is done...What is the content of this "course" that you obviously followed through completely...I am not asking for your opinion; i am asking for facts: explain how GTR can be derived whithout any geometrical models...
Please for once answer my question...
Paul Adrien Maurice Dirac said:One can easily imagine a curved two-dimensional space as a surface immersed in Euclidean three-dimensional space.In the same way,one can have a curved four-dimensional space immersed in a flat space of a larger number of dimensions.Such a curved space is called a Riemann space.A small region of it is approximately flat.
Einsteina assumed that physical space is of this nature and thereby laid the foundation for his theory of gravitation.
For dealing with curved space,one cannot introduce rectilinear system of axes.One has to use curvilinear coordinates such as those dealt with in Section 3.The whole formalism of that section can be applied to curved space,because all the equations are ones which are not disturbed by the curvature.
The invariant distance ds between a point [itex] x^{\mu} [/itex] and a neighboring point [itex] x^{\mu}+dx^{\mu} [/itex] is given by
[tex] ds^{2}=g_{\mu\nu}dx^{\mu}dx^{\nu} [/tex]
like in (2.1).ds is real for a timelike interval and imaginary for a spacelike interval.
With a new network of curvilinear coordinates,the [itex] g_{\mu\nu} [/itex] ,given as functions of the coordinates,fix all the elements of of distance;so they fix the metric.They determine both the coordinate system and the curvature of space.
marlon said:Sure, and how do you think the first law of thermodynamics is formulated ? What mathematical concepts are used ? Maybe total differentials ? i don't know ? And what do these total differentials mean and represent physically ?
dextercioby said:Thermodynamics can be taught without making too much mathematical analysis of the differential forms like differential heat and differential work.
marlon said:What said anything about Gibbs here ? Please do not bring in topics that have NOTHING to do with this...Let's stick to the facts at hand
marlon said::rofl: :rofl: :rofl: :rofl: :rofl:
Nothing is more practical then a good theory...ofcourse you first need to understand it...
marlon
dextercioby said:Section "5" from Mr.Dirac course is called "CURVED SPACE" and is:
Marlon,if that's a way to describe curved space-time in GR,then I'm i going to go to bed... :yuck: I'm not saying it's ballooney,it's that it is outrageously simplistic and mathematically unfounded.
By "mathematical analysis" i obviously meant "differential geometry".Telling the students:"[itex]dU [/itex]is a total differential,but [itex] \delta Q [/itex] and [itex] \delta L [/itex] aren't "is not diferential geometry,by no means...
I see Gibbs' work provokes you the same feeling of "uncertainty" as do the words "experimental physics" to me...
But really, where do you get these false arguments. What you say here is just plain wrong man !For your knowledge,Gibbs rebuilt thermodynamics and took over from where Boltzmann had placed statistical physics.
An exterior product is a type of mathematical operation used in the field of linear algebra. It is used to calculate the area or volume of a geometric shape in a higher-dimensional space.
An exterior product is calculated by taking the cross product of two vectors. This results in a new vector that is perpendicular to both of the original vectors and has a magnitude equal to the area or volume of the shape they form.
The main difference between an exterior product and a dot product is the type of result they produce. An exterior product results in a vector, while a dot product results in a scalar. Additionally, an exterior product is only defined for vector spaces with more than three dimensions, while a dot product is defined for any number of dimensions.
The exterior product has many practical applications in fields such as physics, engineering, and computer graphics. It is used to calculate the moment of inertia in physics, the torque in engineering, and the surface area in computer graphics.
One limitation of the exterior product is that it is only defined for vector spaces with an even number of dimensions. Additionally, it can only be used for calculating the area or volume of certain types of shapes, such as polygons and polyhedra.