Extracting a constant variable from integral

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A constant variable "b" can be extracted from an integral through substitution, which is a valid technique in calculus. When changing the variable of integration, the differential d(x/b) simplifies to dx/b, allowing the constant to be factored out. This manipulation demonstrates how integrals can be adjusted by altering the variable being integrated. The discussion emphasizes that this method is a useful trick for handling integrals. Understanding this concept is beneficial for those studying classical physics and calculus.
shanepitts
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Sorry for the simplicity of the question but I encountered a simple math problem whilst autodidacting myself on classical physics. I seen that a surplus of a specific constant variable "b" was extracted from an integral after a bit of manipulation.

∫xdx was turned into b2∫(x/b)d(x/b)

Does the extra constant b come from the d(x/b)? If so, or if not, how can one change what the integral is being integrated with respect to?

This question is a not a homerwork question.

Thank You
 
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If b is a constant, then yes that is valid. We can change the variable you are integrating with respect to, with substitution, and it's a nifty trick for integrals.

d(x/b) is jus dx/b or (1/b) dx so you can take the constant term out like that.
 
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Paul Eccles said:
If b is a constant, then yes that is valid. We can change the variable you are integrating with respect to, with substitution, and it's a nifty trick for integrals.

d(x/b) is jus dx/b or (1/b) dx so you can take the constant term out like that.
Awesome, thanks a bunch
 
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