F = m x a, but what if velocity is constant (making a zero)?

[lrl4565]

So, Force = Mass x Acceleration. Alright, but what happens when a 400 pound truck hits you going at a constant velocity of 70 miles per hour? Acceleration is 0. Does this mean that the truck exerts no force?

 

[rcgldr]

You're acceleration wouldn't be zero, you'd accelerate from 0 to 70 mph or more depending on how elastic you are (how fast you bounce off). The truck would slow down quite a bit if it only weighed 400lbs.

 

[n.karthick]

Certainly it will exert a force, but momentum will be conserved.

 

[hikaru1221]

No. When you are still in contact with the truck, the truck does exert force on you, which is why you gain speed from zero when being hit. The time period of the contact is typically very small, which I think leads to your misconception that the truck exerts no force. Only after you lose the contact, it no longer exerts any force, and you will travel to the hospital at the constant speed 70 miles/hour if there is no friction or nothing on your way.

 

[phyzmatix]

So, Force = Mass x Acceleration. Alright, but what happens when a 400 pound truck hits you going at a constant velocity of 70 miles per hour? Acceleration is 0. Does this mean that the truck exerts no force?

You've received three replies, I know, but let's put it all together. Let's refer back to Newton's Laws of Motion


In this case, the truck is subject to Newton's first Law

Every body will persist in its state of rest or of uniform motion (constant velocity) in a straight line unless it is compelled to change that state by forces impressed on it. This means that in the absence of a non-zero net force, the center of mass of a body either is at rest or moves at a constant velocity.

You, however, will be subject to the second

A body of mass m subject to a force F undergoes an acceleration a that has the same direction as the force and a magnitude that is directly proportional to the force and inversely proportional to the mass, i.e., F = ma. Alternatively, the total force applied on a body is equal to the time derivative of linear momentum of the body.

You will experience an impulse as the impact with the truck accelerates your body from its stationary state, so (as previously mentioned) the truck's acceleration is zero i.e. there are no forces (ideal world) exerted on the truck whereas your acceleration will be >0 i.e. there will be a force exerted on you by the truck (and on the truck by you, 3rd law).

Makes sense?

 

[inky]

I think before collision speed of truck is constant but after collision speed is not constant. So it has acceleration. Now we can consider force.

 

[Doc Al]

So, Force = Mass x Acceleration. Alright, but what happens when a 400 pound truck hits you going at a constant velocity of 70 miles per hour? Acceleration is 0. Does this mean that the truck exerts no force?

Force = mass X acceleration refers to the net force on an object. As long as the truck moves at a constant velocity, the net force on the truck will be zero. Of course, as soon as the truck hits you, it will no longer be moving at a constant velocity--there will be a non-zero acceleration. You and the truck will definitely exert forces on each other.

 

[arildno]

In order to find out the (average) magnitude of the force couple you and the car exert upon each other during the colllision, you'll need to know the a) mass of at least one of the objects, b) the velocities of that object just before, and just after the collision, and c) the time the collision took.

Let us define these cquantities as:
m, v_{before},v_{after},T

Thus, the force upon the object during the collision is roughly given by:
F=m\frac{v_{after}-v_{before}}{T}
Note that for even a "tiny" velocity difference, the force might be enormous, if the time interval over which the velocity change happened was even tinier.

 

[pahr samsalah]

The answer is in your question .Since the truck is deaccelerating from 70mileshr-1 to 0mileshr-1 .Since this change is taking place in time 't' so a=70/t.
Practically this time will be very small (i.e in the order of 1*10^-1) so this force must be very large (i.e a=70/10^-4=7x10^-5 , assuming t=10^-4).But since it acts only for a short time therefore change in momentum is small and not very large.

 

[Ali Inam]

Obviously, there will be force when the truck is about to hit us while coming with a great speed but as you say the acceleration will be zero, so it will face retardation at the point of impact on you and naturally hit you with a THUMP !


We supposed this example after removing friction, didn't we ? !

 

[Fredrik]

The acceleration isn't going to be zero when the truck makes contact with you. Anyway, the acceleration of the truck is only relevant when you want to know the force that you exert on the truck. If you want to know the force that the truck exerts on you, it's your acceleration that matters, and I can assure you that it will be substantial.