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F(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and

  1. Feb 24, 2009 #1
    f(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and an inflection point at x=1. the values of a and b are...?

    ok im really stuck.
    thanks in advance!
     
  2. jcsd
  3. Feb 24, 2009 #2

    rock.freak667

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    Homework Helper

    you have a point on the graph (0,1), when x=0, f(x)=1...you can get one constant.

    at a point of inflexion f''(x)=0
     
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