F(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and

  • Thread starter meredith
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f(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and an inflection point at x=1. the values of a and b are...?

ok im really stuck.
thanks in advance!
 

Answers and Replies

  • #2
rock.freak667
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you have a point on the graph (0,1), when x=0, f(x)=1...you can get one constant.

at a point of inflexion f''(x)=0
 

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