F(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and

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SUMMARY

The function f(x) = x^4 + ax^2 + b has a relative maximum at the point (0,1) and an inflection point at x=1. To find the constants a and b, it is established that f(0) = 1, leading to the equation b = 1. Additionally, the second derivative f''(x) must equal zero at the inflection point, providing a method to derive a specific value for a. By solving these equations, the values of a and b can be determined definitively.

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meredith
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f(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and an inflection point at x=1. the values of a and b are...?

ok I am really stuck.
thanks in advance!
 
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you have a point on the graph (0,1), when x=0, f(x)=1...you can get one constant.

at a point of inflexion f''(x)=0
 

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