Factory Power From Total Current

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SUMMARY

The discussion centers on calculating the real power dissipated by a factory operating at 120V with a total electric current of 1.2 amperes and a phase angle of 2.1 radians. The formula used is P = Vrms x Irms x pf, where Vrms is 120V and Irms is 1.2A. The phase angle conversion raised concerns about its validity, as a phase angle of -120 degrees suggests power generation rather than consumption. The consensus indicates that the current value of 1.2A is likely an RMS value, which is standard for AC measurements.

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1.A small factory utilizes the standard 120V/Hz voltage. When all the heavy machinery is operational, the total electric current flowing into the factory is 1.2 amperes. The phase angle between the voltage and current waveforms is measured to be 2.1 radians. Find the real power dissipated by the factory. Round off your answer to two decimal places.



2. P = Vrms x Irms x pf



3.Vrms = 120, Irms = 1.2?, I converted 2.1 to degrees and got 120.321. I thought it would just be 120 x 1.2 x cos(120.321).
 
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Are you sure you have these figures correct? A current of 1.2A is unrealistic. That's the current for a pair of small light globes.

The phase angle should lie between 0 and -90 degrees. If it indeed is -120 degrees, this implies that the factory is generating power.

Is this likely to be a trick question?
 
From your identical thread: that 1.2A can be assumed to be RMS, that's how AC quantities are usually specified (by default).
 

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