Falling mass onto flat plate pressure exerted

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Homework Help Overview

The discussion revolves around an experiment designed to measure soil pressure exerted on grass seeds (lolium perenne) using a flat plate. The original poster seeks to determine the height needed to jump in order to exert a specific pressure of around 30 kPa, given their mass and the area of the plate.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the feasibility of using jumping to exert pressure and suggest alternative methods, such as using a frame to apply continuous pressure. The original poster expresses concerns about the complexities of soil dynamics and the implications of using different plate sizes.

Discussion Status

There are multiple lines of reasoning being explored, including the effectiveness of jumping versus continuous pressure application. Some participants have offered alternative suggestions, but there is no explicit consensus on the best approach to achieve the desired pressure.

Contextual Notes

The original poster has indicated a lack of precision is acceptable for their experiment and has mentioned the existence of a control area with no pressure applied. There is also a note about the time period of pressure application being very short, akin to the dynamics of jumping.

llamedos
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Homework Statement



hi I'm trying to design a small experiment based on soil pressure
i've not had much use of some of the equations and principles for a few years so I'm a little rusty

basically I'm trying to exert pressures onto grass seeds (lolium perenne) in a rough field experiment in order to see how it affects germination rates

effective material
small flat plate 0.25m*0.25m for this purpose it is effectively massless
me approx mass 100kg

i can exert approx 15-16kPa by standing on the plate
but I'm trying to calculate how high i need to jump to exert around 30kPa

looking for a max pressure
i'd assume soil compression to be about 2 cm from surface height
i don't need high precision but a rough and ready approximation

ignore any mitigation by the body i.e knees and ankles

any help gratefully received

Homework Equations


mass m = 100kg
grav = g = 9.8m/s^2
area = a = 0.0625m^2


The Attempt at a Solution

 
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welcome to pf!

ih llamedos! welcome to pf! :smile:
llamedos said:
i can exert approx 15-16kPa by standing on the plate
but I'm trying to calculate how high i need to jump to exert around 30kPa …

jumping will only exert a very temporary pressure, probably totally useless for your purposes

easier would be to erect a frame with a bar going over your head, so that you can push up against it to press down on the plate continuously …

and you can put ordinary bathroom scales on the plate to show you the force

btw, i assume you'll have a control area with an identical plate with no pressure on it? :wink:
 
its a form of simulated rolling so effective time period is about 0.1 seconds and lower
which is similar to the exertion period of jumping on it

yes there is a control i don't do anything to it

but i could get lost in the complexities of soil matrix dynamics under compressive forces and incident periods so i don't want to.

also when i say field i literally mean field
cutting a plate with half the area and using it twice could work but then there would be the challenge of compensating for more edge effects

on another note i joined back in 2007 when i was doing my a-levels been lurking ever since but never really needed to ask for assistance
 
llamedos said:
its a form of simulated rolling so effective time period is about 0.1 seconds and lower
which is similar to the exertion period of jumping on it

yes there is a control i don't do anything to it

but i could get lost in the complexities of soil matrix dynamics under compressive forces and incident periods so i don't want to.

also when i say field i literally mean field
cutting a plate with half the area and using it twice could work but then there would be the challenge of compensating for more edge effects

on another note i joined back in 2007 when i was doing my a-levels been lurking ever since but never really needed to ask for assistance

(if you want to simulate rolling, why not use an actual roller? :confused:)

let's see … if a roller with mass M passes over the area of a plate in time t,

then that's an impulse (force times time) of Mgt​

if your own mass is m, and your centre of mass rises by a height h (from crouch position to maximum position), then the impulse is the initial change in momentum, = mvi, = m√(2gh)

(if you both jump from the plate and land on the plate, then that's multiplied by 2)

so for the same effect you need h to be (M/m)2t2g/2
 

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