- #1

kobulingam

- 10

- 0

Faraday's law states that induced emf in a conducting loop by a changing flux, say x, is:

emf = dx/dt

Now if we have a circuit with the loop in series with wires (which are then tied together), how do I picture the voltages/currents in this circuit?

I mean, the actual conducting loop taking the changing flux gets the voltage "across" it, correct?

So if I wanted to calculate the current in this circuit, I just divide the voltage of the conducting loop by it's resistance (ignoring the extra stubs of wires which are in series with this), correct?

BUT, if above is correct, what if the wires have a lot of resistance, say 10 times the resistance of the wire loop?