I am working out of the 2010 lindeburg book which can be found here. The solution is in the book so I am actually looking for an explanation rather than a solutution. http://www.scribd.com/doc/113765067/FE-Review-Manual-Lindeburg-2010 [Broken] this is chapter 10 pg 8 in the chapter, reviewing the PDF its pg 163 on scribd. Problem # 2 1. The problem statement, all variables and given/known data Given Line P and Q which intersect at a 70 degree angle. A force F is applied between them at 25 degrees from p and 45 degree from Q. Find Fp and Fq 2. Relevant equations Trig related 3. The attempt at a solution My approach was simply to orient the system with line P being the x axis. Thus Fp should be 300cos(25) and because we know the angle between F and Q, Fq should also be easy to resolve as 300cos(45). Both answers are wrong Lindeburg provides the solution as Fy=Fsin(25)=Fqsin(70) thus Fq=Fsin(25)/sin(70), Which I can see and understand. However for his Fp he initially uses the Fcos(25) then subtracts Fqcos(70). I am curious to know the following 1. Why simply using the force multiplied by the cosine of the angle between the vector and direction doesn't work. This approach does work for x,y force components. 2. If P and Q are simply directional lines why Fq has any relevance on the magnitude of Fp Thank you for looking.