# Feynman exercise - container with steel balls

## Homework Statement

You received many steel balls of the same diameter d and container of known volume V. All dimensions of the container are much greater than balls diameter. How many balls can be placed in a container?

## Homework Equations

$$(\frac{4}{3}\pi)(\frac{d^3}{8})\approx0,52d^3$$

## The Attempt at a Solution

To place balls in a container we should arrange this container with in a certain order. Let's assume that this balls will be organised such that centres every eight of the bullets will be in vertices of cube. Of course, the length of side of the cube will be equal in diameter of bullet d. For each cube one bullet. Calculating using this formula $$(\frac{4}{3}\pi)(\frac{d^3}{8})\approx0,52d^3$$ we conclude that bullets occupy 52% of the available area.

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haruspex
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Hubot, you have not made it clear what you are asking of the forum. Nor is it clear what information was provided to you, what exactly was the question asked of you, and what parts are your attempt at solution.