Fibre Optic Questions: Understanding Cladding and Critical Angle

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SUMMARY

This discussion focuses on the role of cladding in fibre optics, specifically how a cladding with a refractive index lower than that of the core increases the critical angle. The mathematical relationship is established through the equation sinθc = N(cladding)/N(glass), demonstrating that cladding enhances total internal reflection (TIR) by allowing light to enter the fibre at a wider range of angles. Increasing the critical angle is beneficial as it improves light confinement within the core, optimizing signal transmission. The discussion emphasizes that understanding the mathematics of optics directly correlates with grasping the underlying principles.

PREREQUISITES
  • Understanding of refractive indices in optics
  • Familiarity with the concept of total internal reflection (TIR)
  • Basic knowledge of sine functions and their properties
  • Mathematical skills to interpret optical equations
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  • Study the mathematical derivation of critical angles in various materials
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Optical engineers, telecommunications professionals, and students studying fibre optics who seek to deepen their understanding of light propagation and the significance of cladding in optical fibres.

fibreoptic
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Hi, I have some fibre optics questions that I can't seem to get my head around.

How does providing a cladding of a refractive index slightly lower than the core increase the critical angle? I can do the mathematics to see that it does however is there a logical explanation.
Why is increasing the critical angle a good thing? Doesn't that mean that less light will undergo TIR and will be refracted instead?

If for example the critical angle was 20 deg then surely the incoming light could hit at a smaller angle and still undergo TIR, if the critical angle is higher then there is a smaller window for TIR?
 
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For the critical angle between the glass core and the cladding material, sinθc=N(cladding)/N(glass). The sine function is monotonously increasing between 0 and π/2, so the cladding increases the critical angle with respect to no-cladding, when the sine of the critical angle would be 1/N(glass).
The advantages of cladding are shown here http://www.schoolphysics.co.uk/age16-19/Optics/Refraction/text/Fibre_optics/index.html

ehild
 
Math is logic. If you can do the math than you do understand the logic.
 

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