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Final velocity and frictional force?

  1. Oct 14, 2011 #1
    1. The problem statement, all variables and given/known data

    a) A jet fighter has two engines each generating 70,000 N of thrust. What is the acceleration of the 15,000 kg jet?


    b) The above jet reaches a final velocity of 240 m/s. What is the frictional force on the jet?

    2. Relevant equations
    Ff= Fn(mew?)
    F=MA
    ?


    3. The attempt at a solution
    Okay, so for the first part (a) I got 4.66 m/s squared as my acceleration. I need to know how to get the answer for part b.
     
  2. jcsd
  3. Oct 14, 2011 #2
    Hi there, welcome to the forum.
    Since the question deals with a flying object, I assume the frictional force mentioned is one of the viscuous property that requires the solution of a differential equation.
    If you care for it, and your level of studies satisfies it, it goes something likes this:
    A frictional force, acting in a medium such as air, is typically proportional to the velocity, like -k*v, so we get:
    [itex]
    \large
    F-kv(t) = mv'(t)
    [/itex]
    Which leads to the general solution:(assuming the jet started off at zero initial speed)
    [itex]
    \large
    v(t)=\frac{F}{k}(1-e^{-\frac{kt}{m}})
    [/itex]
    The final velocity is obtained somewhere in infinity, or V(final) = F/k;
    You're given V_final, so you can easily find the constant k, which will lead you to the frictional force, -k*v, your mu.
    Hope that helps,
    Daniel
     
  4. Oct 14, 2011 #3
    But the jet has two engines.......part a.
     
  5. Oct 14, 2011 #4
    I don't know what level class you are taking but the answer may be very simple for part b. The jet ceases to accelerate when the resistance due to air friction equals the thrust of the TWO engines.
     
  6. Oct 14, 2011 #5
    I think the question, as posited by the author, implied that:
    cumulatively, in unison, all in all, 7*10^4 N;
    As for the friction, I doubt the resistive force is constant, in such a query as this.
    Daniel
     
  7. Oct 14, 2011 #6

    I like Serena

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    Homework Helper

    Welcome to PF, emmyology! :smile:

    I tend to agree with LawrenceC.
    For the answer to (a) I think you need to consider that there are two engines...
    And for the answer to (b) I'm also interpreting the question as meaning the friction when the final velocity is reached, at which time the force of friction exactly cancels the force of the two engines.

    @danielakkerma: I believe friction with air is typically modelled as being proportional to the square of the velocity.
     
  8. Oct 15, 2011 #7
    Thanks for clearing that up, I hope I didn't convolute things...
    As for the resistance, my initial thoughts leaned towards Stoke's law, whose drag is proportional to the velocity itself, given that the speeds here are not quite so massive. But I could be wrong of course, and I am glad you can point us in the proper direction; I wish we could hear from the OP and the respective elucidations which might entail.
    Daniel
     
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