Find 2 linearly independent eigenvectors and a eigenvalue

  • Thread starter bodensee9
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  • #1
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Hi

I am supposed to, without calculation, find 2 linearly independent eigenvectors and a eigenvalue of the following matrix A

5 5 5
5 5 5
5 5 5

The eigenvalue is easy -- it is 15. And I can find one eigenvector, [1 1 1] (written vertically), but another without calculation? Is there a trick that I should see? Of course, zero is also a eigenvalue, but how am I supposed to find the other eigenvector without calculation? Is there something that I should see?

Thanks.
 

Answers and Replies

  • #2
Dick
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Pick the vector (x,y,z) so that 5x+5y+5z=0. Say, (1,1,-2)?
 
  • #3
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oh thanks!
 

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