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Find a,b,c

  1. Jan 11, 2008 #1
    find a,b,c


    tana+tanb+tanc= sq.(3)
  2. jcsd
  3. Jan 11, 2008 #2
    Not too sure if this is solvable in general as you only have 2 equations but 3 unknowns. Are there any other equations/constraints that you didn't post up?

    Generally, you need n equations/constraints to solve for n unknowns.
  4. Jan 11, 2008 #3
    Sure it shouldn't say a+b+c=90?
    Because then we could use
    [tex] tan(30^{\circ}) = \frac{\sqrt{3}}{3}[/tex]
    and get the correct result.
  5. Jan 11, 2008 #4


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    Gold Member

    J.D you could also ask shouldn't it be a+b+c=180 and tg(a)+tg(b)+tg(c)=3sqrt3, cause we can use: tg(60)=sqrt(3).
  6. Jan 11, 2008 #5
    That also makes sense. I really feel that there is something wrong with the original question and have my doubts whether or not there even exist a solution. I have to admit though that I haven't made any serious attempts to prove it.
  7. Jan 11, 2008 #6
    A theory can be used

    then tanget a + tanget b + tanget c = tan a tanb tanc

    tanget a + tanget b + tanget c = sq.3
    tan a tanb tanc= sq.3
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