# Find a,b,c

1. Jan 11, 2008

### m_s_a

find a,b,c

a+b+c=180

tana+tanb+tanc= sq.(3)

2. Jan 11, 2008

### div curl F= 0

Not too sure if this is solvable in general as you only have 2 equations but 3 unknowns. Are there any other equations/constraints that you didn't post up?

Generally, you need n equations/constraints to solve for n unknowns.

3. Jan 11, 2008

### J.D.

Sure it shouldn't say a+b+c=90?
Because then we could use
$$tan(30^{\circ}) = \frac{\sqrt{3}}{3}$$
and get the correct result.

4. Jan 11, 2008

### MathematicalPhysicist

J.D you could also ask shouldn't it be a+b+c=180 and tg(a)+tg(b)+tg(c)=3sqrt3, cause we can use: tg(60)=sqrt(3).

5. Jan 11, 2008

### J.D.

That also makes sense. I really feel that there is something wrong with the original question and have my doubts whether or not there even exist a solution. I have to admit though that I haven't made any serious attempts to prove it.

6. Jan 11, 2008

### m_s_a

A theory can be used
Is

if
a+b+c=180
then tanget a + tanget b + tanget c = tan a tanb tanc

1)
tanget a + tanget b + tanget c = sq.3
2)
tan a tanb tanc= sq.3
3)
????????????????