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## Homework Statement

Let

*V*be the subspace of

*R*

^{3}defined by

*V*={(x,y,z)l2x-3y+6z=0}

Find a basis

*B*for the subspace.

## Homework Equations

## The Attempt at a Solution

First I broke apart the equation such that:

[[x,y,z]] = [[3/2s-3t, s, t]] = s [[3/2, 1 ,0]] +t[[-3, 0, 1]]

So, a basis for V =

[[3/2, 1, 0]

-3, 0, 1]]

Does this sound correct?