Find a Cartesian equation for the curve and identify it.

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tangibleLime
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Homework Statement



Find a Cartesian equation for the curve and identify it.

r = 3sin(θ)

Homework Equations


The Attempt at a Solution



I know that the answer is as follows...

[tex]r^2=3(r*sin(\theta))[/tex]
[tex]x^2+y^2 = 3y[/tex]
[tex]x^2 + (y-\frac{3}{2})^2 = (\frac{3}{2})^2[/tex]

I understand everything but the last part. Where the hell is (3/2) coming from? I know if I want to solve the equation, x can be (3/2) and y can be (3/2) or... but x is still in here and so is y.
 
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tangibleLime said:

Homework Statement



Find a Cartesian equation for the curve and identify it.

r = 3sin(θ)


Homework Equations





The Attempt at a Solution



I know that the answer is as follows...

[tex]r^2=3(r*sin(\theta))[/tex]
[tex]x^2+y^2 = 3y[/tex]
[tex]x^2 + (y-\frac{3}{2})^2 = (\frac{3}{2})^2[/tex]

I understand everything but the last part. Where the hell is (3/2) coming from? I know if I want to solve the equation, x can be (3/2) and y can be (3/2) or... but x is still in here and so is y.
Whoever wrote the answer is completing the square in the y terms.
x2 + y2 - (3/2)y = 0
To complete the square, (3/2)2 must be added to both sides.
 
Oooh thanks. It would have been cool if he said that instead of just doing it (it was a video).