Find a sequence convering to sqrt(2)

[kidsmoker]

Homework Statement

Find a sequence whose limit is \sqrt{2}.

Homework Equations

The work preceeding this was about using recurrence relations to find sequences with desired limits, so that's the method they want me to use.

The Attempt at a Solution

We can find the limit of the sequence given by

a_{n+1} = \frac{1}{2+a_{n}} by noting that a_{n+1} and a_{n} both have the same limit. So we can write

l = \frac{1}{2+l} and find the positive root of that: l = -1 + \sqrt{2}. This is the limit of the sequence.

I can then just add on one to each term to give a sequence with limit \sqrt{2}. Is this all they want me to do you think? Or is there a way to get write another sequence involving a_{n+1} and a_{n} which gives the desired answer?

Thanks.

 

[Hurkyl]

There are gajillions of ways to answer this problem; yours seems fine.

I do have one question, though: were you merely asked to find a sequence, or are you also expected to prove that the sequence converges to \sqrt{2}? If the latter, I would like to point out that your work shows

If the sequence converges, then it converges to \sqrt{2}.​

However, you never showed that the sequence converges, and therefore you cannot conclude that it converges to \sqrt{2}.

 

[kidsmoker]

Yeah I see what you mean. If it was Analysis then i'd have to prove it by showing it's bounded and increasing or whatever. But this module doesn't seem to bother with that. Thanks.