Find Accel. of Cart from Mass m & Theta

  • Thread starter Thread starter greenskyy
  • Start date Start date
  • Tags Tags
    Cart Mass Theta
AI Thread Summary
The discussion revolves around deriving an equation for the acceleration of a cart based on the angle theta and the mass of a hanging ball. Participants express confusion about identifying the forces acting on the system, particularly regarding the cart's forward acceleration without a clear driving force. Key equations involving tension and gravitational forces are presented, but there is uncertainty about their correctness. The conversation also touches on formatting issues for representing theta in the forum. Ultimately, understanding the net forces and conservation principles in the ball-cart system is emphasized as crucial for solving the problem.
greenskyy
Messages
17
Reaction score
0

Homework Statement


http://img188.imageshack.us/img188/9897/73266226.png

The problem is to create an equation to find the acceleration of the cart based upon theta. All that is given is the ball hanging is known as mass m.

Homework Equations


f=ma
f=\frac{mv^{2}}{r}

The Attempt at a Solution


I am assuming that the car is moving to the right, since the hanging mass is tilted backwards. I am really at a loss of even just identifying all the forces exactly. What confuses me the most is that we are assuming the cart is accelerating forward, but there is no force causing it to move forward.


So far, this is what I have:
m being the mass, c being the cart
F_{mx}=Tsin\theta

F_{my}=Tcos\theta - mg

F_{cx}=m_{c}a - Tsin\theta

F_{cy}=-Tcos\theta = 0

I know that these are probably wrong, but can someone please tell me why?
 
Last edited by a moderator:
Physics news on Phys.org


I'm a little confused by all the subscripts! And can't make thetas here.
Vertical: Tcos(A) - mg = 0
Horizontal: Tsin(A) = ma
If you solve one for T and sub in the other, you'll get something that makes sense.

How do you make a theta?

PS it is accelerating to the right because theta > 0. If it wasn't accelerating, it would hang straight. So no need to think about what is making it accelerate.
 


Haha, well you make a theta using latex code. For the theta symbol, it would be [ t e x ] \ t h e t a [ \ t e x ] (minus the spaces)
 


Thank you greenskyy. I fear that is too awkward for me.
I have seen someone with a whole bunch of symbols (theta, pi, etc.) in his signature. I wonder if that is so he can copy a theta whenever he wants it? Do you know how I can have a signature here?
 


Nope, I looked around and couldn't find it anywhere in the user control panel =\
 


What is the net force on the ball-cart system? What quantity is conserved, then?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top