nyyfan0729 Messages 12 Reaction score 0 Thread starter Dec 4, 2005 #1 Using trapezoids and N=4, find the length of the arc of the curve y=(1/3)x^3 from (0,0) to (1,1/3).
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Dec 5, 2005 #2 Of course, [itex]\frac{dy}{dx}= x^2[/itex] so the length of the curve from x= 0 to x= 1 is [tex]\int_0^1 \sqrt{1+ x^4}dx[/tex] By "Using trapezoids" do you mean use the trapezoid rule to numerically integrate that?
Of course, [itex]\frac{dy}{dx}= x^2[/itex] so the length of the curve from x= 0 to x= 1 is [tex]\int_0^1 \sqrt{1+ x^4}dx[/tex] By "Using trapezoids" do you mean use the trapezoid rule to numerically integrate that?