# Find charge density of simple electric field

• doodlepin
In summary, the electric field points in a particular direction, when the charge density is uniform. To account for this, you integrate over a cylinder having flat faces parallel to the yz plane, on face with positive x-coordinate, the other with negative x-coordinate.
doodlepin

## Homework Statement

Suppose an electric field E(x,y,z) has the form:

E_x = ax, E_y = 0, E_z = 0

where a is a constant. What is the charge density? How do you account for the fact that the field points in a particular direction, when the charge density is uniform?

## Homework Equations

charge density = charge per unit volume

gauss's law says the volume integral of the electric field around some closed surface is negative the charge enclosed divided by the epsilon constant

## The Attempt at a Solution

I picture this as an infinite charged plate going through x = 0 in the yz plane, which would have purely an electric field in the x-direction. So i think I am supposed to use gauss' law and integrate over all space? But i think that would get me some kind of infinite solution? Any hints would be greatly appreciated.

Is this the complete statement of the problem? - word for word?

Yes. Except for a quick blurb in parenthesis saying: (This is a more subtle problem than it looks, and worthy of careful thought)

doodlepin said:

## Homework Statement

Suppose an electric field E(x,y,z) has the form:

E_x = ax, E_y = 0, E_z = 0

where a is a constant. What is the charge density? How do you account for the fact that the field points in a particular direction, when the charge density is uniform?

## Homework Equations

charge density = charge per unit volume

Gauss's law says the volume integral of the electric field around some closed surface is negative the charge enclosed divided by the epsilon constant

## The Attempt at a Solution

I picture this as an infinite charged plate going through x = 0 in the yz plane, which would have purely an electric field in the x-direction. So i think I am supposed to use gauss' law and integrate over all space? But i think that would get me some kind of infinite solution? Any hints would be greatly appreciated.
(My Gauss's Law has no negative in it. Electric field originates on positive charge and terminates on negative.)

Assuming that you have "an infinite charged plate going through x = 0 in the yz plane", then you don't need to integrate over the whole plate. Integrate over a cylinder having flat faces parallel to the yz plane, on face with positive x-coordinate, the other with negative x-coordinate. Other sides should be parallel to the x-axis (perpendicular to the yz plane).

If the area of a flat face is A, how much flux passes through each surface of the cylinder?

How much charge is enclosed by the cylinder?

How much area of the plate is enclosed by the cylinder?

SammyS said:
(My Gauss's Law has no negative in it. Electric field originates on positive charge and terminates on negative.)

Assuming that you have "an infinite charged plate going through x = 0 in the yz plane", then you don't need to integrate over the whole plate. Integrate over a cylinder having flat faces parallel to the yz plane, on face with positive x-coordinate, the other with negative x-coordinate. Other sides should be parallel to the x-axis (perpendicular to the yz plane).

If the area of a flat face is A, how much flux passes through each surface of the cylinder?

How much charge is enclosed by the cylinder?

How much area of the plate is enclosed by the cylinder?

Flux that passes through each end of the cylinder:
E is independent of surface area at end of cylinder so flux is just E*A = ax*A
where A is the area of the end of the cylinder.

Charge enclose by the cylinder is charge density of infinite plane multiplied by A

Area of plate enclosed by the cylinder is A.

I don't have any further understanding of what the charge density of space is.

The charge density will be an area density, i.e. charge per unit area, σ.

So, the amount of charge on a surface of area A is Qin = σ·A .

Ok i understand that. Do you have any idea what they are asking for though? Because there is no area which would cover the entire yz plane. The gaussian cylinder thing makes since to me, i just don't know how it applies to finding the charge density of an infinite plane.

## Question 1: What is charge density?

Charge density is a measure of the amount of charge per unit volume in a given region of space. It is typically denoted by the Greek letter rho (ρ) and is expressed in units of coulombs per cubic meter (C/m³).

## Question 2: How do you calculate charge density?

To calculate charge density, you need to know the total amount of charge (Q) and the volume (V) of the region in which the charge is located. The charge density (ρ) can then be calculated using the formula ρ = Q/V.

## Question 3: What is a simple electric field?

A simple electric field is a type of electric field that is created by a single, stationary charge. It is characterized by its direction and strength, and can be represented by electric field lines.

## Question 4: How do you find the charge density of a simple electric field?

To find the charge density of a simple electric field, you can use the formula ρ = ε0 * E, where ε0 is the permittivity of free space and E is the electric field strength. This formula assumes that the electric field is uniform and only caused by a single charge.

## Question 5: What is the unit for charge density?

The unit for charge density is coulombs per cubic meter (C/m³). This unit is derived from the SI units for charge (coulombs) and volume (cubic meters).

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