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anemone
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Find a closed form expression for \(\displaystyle \sum_{k=1}^{n^2}\dfrac{n-\lfloor\sqrt{k-1}\rfloor}{\sqrt{k}+\sqrt{k+1}}\).
anemone said:Find a closed form expression for \(\displaystyle \sum_{k=1}^{n^2}\dfrac{n-\lfloor\sqrt{k-1}\rfloor}{\sqrt{k}+\sqrt{k+1}}\).
anemone said:Thank you kaliprasad for your clever solution and sorry for the late reply...:(
I will share with you the quite similar but not completely the same solution with you and MHB:
Note that
$\begin{align*}\displaystyle \sum_{k=1}^{n^2}\dfrac{n-\lfloor\sqrt{k-1}\rfloor}{\sqrt{k}+\sqrt{k+1}}&=\sum_{m=1}^{n}\sum_{k=(m-1)^2+1}^{m^2}\dfrac{n-\lfloor\sqrt{k-1}\rfloor}{\sqrt{k}+\sqrt{k+1}}\\&=\sum_{m=1}^{n}\sum_{k=(m-1)^2+1}^{m^2}\dfrac{n-(m-1)}{\sqrt{k}+\sqrt{k+1}}\\&=\sum_{m=1}^{n}(n-m+1)\sum_{k=(m-1)^2+1}^{m^2}\dfrac{1}{\sqrt{k}+\sqrt{k+1}}\\&=\sum_{m=1}^{n}(n-m+1)\sum_{k=(m-1)^2+1}^{m^2}\sqrt{k}-\sqrt{k+1}\\&=\sum_{m=1}^{n}(n-m+1)(m-(m-1))\\&=\sum_{m=1}^{n}(n-m+1)\\&=n(n+1)-\dfrac{n(n+1)}{2}\\&=\dfrac{n(n+1)}{2}\end{align*}$
A closed form expression is a mathematical expression that can be written using a finite number of mathematical operations and constants, such as addition, subtraction, multiplication, division, and exponentiation.
To find a closed form expression for a given sum, you need to identify the pattern or relationship between the terms in the sum. Then, you can use algebraic techniques to manipulate the terms and simplify the expression into a closed form.
The purpose of finding a closed form expression is to have a more concise and general representation of a sum. This can make calculations and evaluations easier and more efficient, especially for large sums.
No, not all sums have a closed form expression. Some sums may involve complex patterns or relationships that cannot be expressed using a finite number of mathematical operations and constants.
Yes, there are some limitations to using closed form expressions for sums. For example, some closed form expressions may only be valid for a certain range of values or may not be able to accurately represent the sum for all values. Additionally, some sums may not have a closed form expression that can be easily derived or understood.