Find Current Through R2: Mesh Analysis

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SUMMARY

The discussion focuses on determining the current through resistance R2 using mesh analysis in a circuit. The user presents their equations for three loops, identifying Loop 1 with a current of I1=1A, Loop 2 as R3(I2-I3)+R4(I2-I1)=12, and Loop 3 as -R1(I3-I1)+R3(I3-I2)-R2I3=0. A critical observation is made regarding Loop 3, where it is noted that all signs should be consistent, either all positive or all negative, to ensure accurate calculations.

PREREQUISITES
  • Understanding of mesh analysis in electrical circuits
  • Familiarity with Ohm's Law and Kirchhoff's Voltage Law
  • Basic knowledge of circuit components such as resistors (R1, R2, R3, R4)
  • Ability to solve simultaneous equations
NEXT STEPS
  • Review mesh analysis techniques for complex circuits
  • Practice solving simultaneous equations in electrical engineering contexts
  • Explore the implications of sign conventions in circuit analysis
  • Learn about circuit simulation tools to verify mesh analysis results
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone interested in mastering mesh analysis for circuit current calculations.

sea.flea
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Hello everybody on the physics forum, i was just looking for someone to point me in the right direction and tell me if my equations are right

Homework Statement


Determine the current though the resistance R2 by mesh analysis
http://www.freeimagehosting.net/uploads/a77e95d378.jpg

The Attempt at a Solution


Ok, this is what i have so far:
Loop 1: I1=1A
Loop 2: R3(I2-I3)+R4(I2-I1)=12
Loop 3: -R1(I3-I1)+R3(I3-I2)-R2I3=0
 
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Yeah it looks ok to me. Just solve for I2 and I3.
 
sea.flea said:
Hello everybody on the physics forum, i was just looking for someone to point me in the right direction and tell me if my equations are right

Homework Statement


Determine the current though the resistance R2 by mesh analysis
http://www.freeimagehosting.net/uploads/a77e95d378.jpg

The Attempt at a Solution


Ok, this is what i have so far:
Loop 1: I1=1A
Loop 2: R3(I2-I3)+R4(I2-I1)=12
Loop 3: -R1(I3-I1)+R3(I3-I2)-R2I3=0

In loop 3 all signs should be the same (positive or negative)
 

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