How to do Mesh Analysis with current controlled voltage source

  • Thread starter eehelp150
  • Start date
  • #1
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Homework Statement


Vs = 100cos(2000t)
upload_2016-11-7_21-11-57.png


Homework Equations


KVL, KCL

The Attempt at a Solution


My mesh equations are:
-Vs + I1(30-12.5j)-I2(120j)=0
4Ix+I2(120j+20)-I1(120j)=0
Ix = (I1-I2)

Are these correct? When I solve I get a different result than when I do nodal analysis.
 

Answers and Replies

  • #2
gneill
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Your first mesh equation is missing a term for the potential drop over the inductor due to mesh current ##I1##.
 
  • #3
237
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Your first mesh equation is missing a term for the potential drop over the inductor due to mesh current ##I1##.
-Vs + I1(30-12.5j+120j)-I2(120j)=0

i1 = (1.93736+0.385512i)
i2 = (1.83193+0.694348i)

ix = (1.93736+0.385512i)-(1.83193+0.694348i)
V(120j) = ix*120j = 37.06+j12.65 V
The solution (using nodal analysis) says V(120j) = 2.95+j1.126
 

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