Find derivative at 1 of this complicated function

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SUMMARY

The discussion focuses on finding the derivative of the implicit function defined by the equation sin(y)sin(πx/2) + 31/2/2(sec(-12x)) + 2x(tan(ln(x+2))) = 0 at the point x = -1. A key challenge identified is the differentiation of ln(sin(πx/2)), which raises concerns about the logarithm of a negative number. The correct interpretation of the function is clarified as (sin y)sin(πx/2), not sin(y^(sin(πx/2))).

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with trigonometric functions and their derivatives
  • Knowledge of logarithmic differentiation
  • Basic calculus concepts, including limits and continuity
NEXT STEPS
  • Study implicit differentiation techniques in calculus
  • Explore the properties and derivatives of trigonometric functions
  • Learn about logarithmic differentiation and its applications
  • Review the concept of limits, particularly with negative inputs in logarithmic functions
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Students beginning their journey in calculus, particularly those learning differentiation techniques, and anyone seeking to understand implicit functions and their derivatives.

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Homework Statement


find dy/dx at x=-1 .

Homework Equations


sin ysin pi*x/2 + 31/2/2(sec-12x) +2x(tan(ln(x+2)))=0

The Attempt at a Solution


There is coming a term ln(sin pi*x/2) during differentiation which will be a ln of a negative number. Sorry if the problem is too easy .I am just starting differentiation.
 
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Is that really [tex]\sin (y^\frac{sin \pi x}{2})[/tex]?
 


no it is (sin y)sin (pi*x/2)
 

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