Find direction of tangent line to equation

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Homework Help Overview

The discussion revolves around finding the direction of the tangent line to the curve defined by the equation x4 + y4 = 32 at the point (2, -2). The subject area is vector calculus, specifically focusing on implicit differentiation and the properties of gradients.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the gradient to find the tangent line, with one participant suggesting that the gradient might be 4x3i + 4y3j. There is uncertainty about whether this gradient correctly represents the direction of the tangent line at the specified point. Another participant points out that the direction given is actually that of the greatest slope, indicating a need to find the perpendicular direction for the tangent line.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between the gradient and the tangent line. Some guidance has been provided regarding the need to find a perpendicular vector, but there is no explicit consensus on the method to achieve this or the correct interpretation of the gradient.

Contextual Notes

Participants are grappling with the implications of using implicit differentiation and the geometric interpretation of gradients and tangent lines. There is a mention of the need to rotate vectors to find perpendicular directions, but the specifics of the calculations remain unclear.

ArcanaNoir
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Homework Statement



Find the direction of the line tangent to the curve [itex]x^4+y^4=32[/itex] at the point [itex](2, -2)[/itex]

Homework Equations



Anything goes, we're in vector calculus now.

The Attempt at a Solution



So, to find the tangent line, I was thinking of taking the gradient, but I'm not sure how to do that since the curve is in a squirrely format. I think they call that "implicit".

Perhaps the gradient is [itex]4x^3i+4y^3j[/itex]?

and then at the given point we would have [itex]32i-32j[/itex]

Is this actually the direction of the line tangent to the curve at the given point? Is this actually the answer? I don't really know.
 
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ArcanaNoir said:

Homework Statement



Find the direction of the line tangent to the curve [itex]x^4+y^4=32[/itex] at the point [itex](2, -2)[/itex]

Homework Equations



Anything goes, we're in vector calculus now.

The Attempt at a Solution



So, to find the tangent line, I was thinking of taking the gradient, but I'm not sure how to do that since the curve is in a squirrely format. I think they call that "implicit".

Perhaps the gradient is [itex]4x^3i+4y^3j[/itex]?

and then at the given point we would have [itex]32i-32j[/itex]

Is this actually the direction of the line tangent to the curve at the given point? Is this actually the answer? I don't really know.
No. [itex]32\hat{i}-32\hat{j},,[/itex] is the direction of greatest slope. The tangent line is perpendicular to this.
 
darn. so how do I find the perpendicular to that?
 
ArcanaNoir said:
darn. so how do I find the perpendicular to that?
Rotate the vector 90°.
 
Remember doing lines perpendicular to a line how did you figure out the slope?

Negative inverse right?
 

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