Find Equation for Tangent Line to y=e^x at Origin

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Homework Statement


Find an equation for a line that is tangent to the graph of y=ex and goes through the origin.

Homework Equations


The Attempt at a Solution


y'=ex

That's about all I can think of. I don't know how to make the tangent line go through the origin. Can someone lead me in the right direction?
 
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iRaid said:

Homework Statement


Find an equation for a line that is tangent to the grpah of y=ex and goes through the origin.


Homework Equations





The Attempt at a Solution


y'=ex

That's about all I can think of. I don't know how to make the tangent line go through the origin. Can someone lead me in the right direction?

At any point (x,y) on the graph, how would you compute the slope of the tangent line?

RGV
 
Ray Vickson said:
At any point (x,y) on the graph, how would you compute the slope of the tangent line?

RGV

Find the derivative at that point.
 
And you have already said that the derivative is again [itex]e^x[/itex].

So the tangent line to [itex]y= e^x[/itex] at [itex]x= x_0[/itex] would be [itex]y= e^{x_0}(x- x_0)+ e^{x_0}[/itex]. Now, what must [itex]x_0[/b] be so that goes through (0, 0)?[/itex]