1. The problem statement, all variables and given/known data Find an equation for the line y=(x^2)lnx at (1,0) 2. Relevant equations 3. The attempt at a solution I took the first derivative of the equation and got y'=2xlnx +x In other equations, it would be simple to find the slope, but at this point I am lost, is the slope 2? It doesn't appear to be in the form of y=mx+b. So I've decided to use f'(1)=2(1)ln1 + 1 = 1 , this gives me the slope of the function at the point (1,f(1)) right? If that's the case, then y=m(x-x_1) + y_1 = 1(x-1) + 0 y=x-1 Just wanted to know if I am close or way off or maybe correct.