1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Find equation tangent to y=(x^2)lnx at (1,0)

  1. Jan 26, 2014 #1
    1. The problem statement, all variables and given/known data
    Find an equation for the line y=(x^2)lnx at (1,0)

    2. Relevant equations

    3. The attempt at a solution
    I took the first derivative of the equation and got y'=2xlnx +x
    In other equations, it would be simple to find the slope, but at this point I am lost, is the slope 2? It doesn't appear to be in the form of y=mx+b.

    So I've decided to use f'(1)=2(1)ln1 + 1 = 1 , this gives me the slope of the function at the point (1,f(1)) right?

    If that's the case, then
    y=m(x-x_1) + y_1
    = 1(x-1) + 0

    Just wanted to know if I am close or way off or maybe correct.
  2. jcsd
  3. Jan 26, 2014 #2


    User Avatar
    Science Advisor
    Homework Helper

    Looks ok to me.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted