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## Homework Statement

Find an equation for the line y=(x^2)lnx at (1,0)

## Homework Equations

## The Attempt at a Solution

I took the first derivative of the equation and got y'=2xlnx +x

In other equations, it would be simple to find the slope, but at this point I am lost, is the slope 2? It doesn't appear to be in the form of y=mx+b.

So I've decided to use f'(1)=2(1)ln1 + 1 = 1 , this gives me the slope of the function at the point (1,f(1)) right?

If that's the case, then

y=m(x-x_1) + y_1

= 1(x-1) + 0

y=x-1

Just wanted to know if I am close or way off or maybe correct.