1. The problem statement, all variables and given/known data Suppose line tangent to graph of y=f(x) at x =3 passes through (-3, 7) & (2,-1). Find f'(3), what is the equation of the tangent line to f at 3? 2. Relevant equations I found the slope of which equals -8/5 Im not sure how to find the equation... do I do y-3=-8/5(x-3)? or is that wrong?