Find Focus of Parabola: y:-(1/4)x^2 + 2x - 5

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Homework Help Overview

The problem involves finding the focus of a parabola given by the equation y = -(1/4)x^2 + 2x - 5. The discussion centers around the mathematical properties of parabolas, specifically the definition and significance of the focus.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to manipulate the equation to find the focus, including completing the square. Some participants question the understanding of what the focus of a parabola is and its relation to polar coordinates.

Discussion Status

Participants are exploring various definitions of the focus, with some providing physical and mathematical perspectives. There is a mix of interpretations regarding the relationship between the vertex and the focus, and guidance is offered on rewriting the equation in standard form to facilitate finding the focus.

Contextual Notes

There is some confusion regarding the definitions and properties of the focus, with references to both Cartesian and polar coordinates. The original poster's approach involves completing the square, but it is unclear if all participants agree on the steps taken so far.

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Homework Statement



Find the focus of parabola: y:-(1/4)x^2 + 2x - 5

The Attempt at a Solution



Multiplying by 4 to get rid of fraction I get:
4y:-x^2 + 2x - 5

I will bring over the -5:
4y+5:-x^2 +2x

Completing Square I obtain:

4y+6:-(x-1)^2


Is all this correct thus far?
 
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Do you know what a focus of a parabola is? I think it has something to do with polar coordinates.
 
The focus is the central point of a parabola I believe. It determines if parabola points up or down
 
bengaltiger14 said:
The focus is the central point of a parabola I believe. It determines if parabola points up or down
That is the extreme point of a parabola, not a focus.

A physical definition for focus could be this: If you shine parallel beams of light on the parabolic surface, it all reflects and focuses in a special point, called a focus. (A parabolic telescope).

A mathematical one: every point of a parabola has equal distances to a line and a point. The point is called a focus.

Further, if you write down the equation of parabola in polar coordinates in its simplest form, the pole is the focus of parabola.
 
Irid said:
That is the extreme point of a parabola, not a focus.

A physical definition for focus could be this: If you shine parallel beams of light on the parabolic surface, it all reflects and focuses in a special point, called a focus. (A parabolic telescope).

A mathematical one: every point of a parabola has equal distances to a line and a point. The point is called a focus.

Further, if you write down the equation of parabola in polar coordinates in its simplest form, the pole is the focus of parabola.

All very true. But you don't NEED polar coordinates. If you write a standard form for the parabola in cartesian coordinates x^2=4ay the vertex is at the origin and the distance from vertex to focus is 'a'. You just have to write your quadratic in a form similar to the standard form. Like (x-x0)^2=4a(y-y0). Now you have vertex at (x0,y0) and distance to focus 'a'.
 

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