Zaza669
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How to find forces in bars BD CD and CE?
Homework Equations
Static[/B]
The Attempt at a Solution
Bd: -2.5 KN
Cd: 0.866 KN
Ce: 1.73 KN
Find Forces in Truss Bars BD, CD and CE
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How to find forces in bars BD CD and CE?
Static[/B]
Bd: -2.5 KN
Cd: 0.866 KN
Ce: 1.73 KN
Buzz Bloom
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Hi Zaza:
Since no one else has posted an answer, I will offer a thought which I hope will be helpful, although I have never previously attempted to analyze this kind of problem.
Since no mention has been made about the nature of the joints between the beams, I assume that torque stresses on the joints can be ignored. You have calculated that the stress on CE is 1.73 KN. I notice that the joint G has a rolling support, and joints C and E are unsupported. I interpret this to mean that any stresses at G due to horizontal forces on AC, CE, and EG will result in G moving left or right, and this motion will relieve any horizontal stresses in AC, CE, and EG. Since any force in CE must be entirely horizontal due to symmetry, the force in bar CE is zero.
Regards,
Buzz
Since no one else has posted an answer, I will offer a thought which I hope will be helpful, although I have never previously attempted to analyze this kind of problem.
Since no mention has been made about the nature of the joints between the beams, I assume that torque stresses on the joints can be ignored. You have calculated that the stress on CE is 1.73 KN. I notice that the joint G has a rolling support, and joints C and E are unsupported. I interpret this to mean that any stresses at G due to horizontal forces on AC, CE, and EG will result in G moving left or right, and this motion will relieve any horizontal stresses in AC, CE, and EG. Since any force in CE must be entirely horizontal due to symmetry, the force in bar CE is zero.
Regards,
Buzz