Find Fourier Series of f(t)=2u(t)-2u(t-2) with T=4s | Step Function Question

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SUMMARY

The Fourier Series representation of the function f(t) = 2u(t) - 2u(t-2) Volts is analyzed for the period T = 4 seconds. The function exhibits a value of 2 Volts from t = 0 to t = 2 seconds, then drops to -2 Volts until t = 4 seconds, before returning to 2 Volts. This confirms the periodic nature of the function, which is essential for Fourier analysis.

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consider f(t)=2u(t)-2u(t-2) Volts between t=0 and t=4 seconds. So i have to find the Fourier Series Representation of this given that T=4 secounds. I am not worried about the Fourier part. If i draw the f(t) function out on graph its 2 Volts from t=0 till t=2 seconds and then wehn it gets to 2 it goes down -2 volts back to Zero Volts , then when it gets to 4 seconds it goes up back to 2 volts correct ?

Is what i stated correct ?
 
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