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Homework Statement
Find the general solution of the differential equation:
y'' + 4y' + 13y' = 169x + 81e^{e-2x}
EDIT: Can't get latex to work.. so :
http://mathbin.net/60293
The Attempt at a Solution
[EQ]13Ax + 4A + 13B + 9Ce^{-2x} = 169x+81e^{-2x}[/EQ]
http://mathbin.net/60294 Now i have no clue how to find A B C... I'm probably over thinking this :P
the answers are 13 -4 and 9...
EDIT2:
So i think i figured out how to get A and C. I divided 169 by 13 and 81 by 9, which makes sense. But what about B?
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