Find gradient at a point and the directional derivative Multivariable calculus

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SUMMARY

The discussion focuses on calculating the gradient of the function f(x,y) = x³ + 2y³ at the point P(1,1) and determining the directional derivative in the direction of the vector A = i - j. The correct approach involves computing the gradient, which is ∇f = (f_x, f_y) where f_x = 3x² and f_y = 6y². At point P, the gradient evaluates to ∇f(1,1) = (3, 6). The directional derivative is then calculated as the dot product of the gradient at P and the unit vector in the direction of A.

PREREQUISITES
  • Understanding of multivariable calculus concepts, specifically gradients and directional derivatives.
  • Familiarity with partial derivatives and their computation.
  • Knowledge of vector operations, particularly dot products.
  • Ability to normalize vectors to obtain unit vectors.
NEXT STEPS
  • Study the computation of gradients in multivariable functions.
  • Learn how to calculate directional derivatives using the dot product.
  • Explore the concept of unit vectors and their significance in directional derivatives.
  • Practice solving similar problems involving gradients and directional derivatives in different contexts.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with multivariable calculus, particularly those needing to calculate gradients and directional derivatives for optimization or analysis of functions.

Nugget3
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Calculate gradient of f
f(x,y)=x^3+2y^3
at point P (1,1)
and the directional derivative at P
in the direction u of the given vector A -> i-j

I tried to attempt this but i honestly don't know where to start. I began to take the partial derivatives of f. I got f'=3x^2dx+6y^2dy, however that answer doesn't seem correct to me.
 
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Nugget3 said:
Calculate gradient of f
f(x,y)=x^3+2y^3
at point P (1,1)
and the directional derivative at P
in the direction u of the given vector A -> i-j

I tried to attempt this but i honestly don't know where to start. I began to take the partial derivatives of f. I got f'=3x^2dx+6y^2dy, however that answer doesn't seem correct to me.

What you have calculated is the total differential of f(x,y), which includes both partials ##f_x## and ##f_y##. What is the formula for the directional derivative? Show us what happens when you try to calculate it.
 
it is the dot product of the gradient at P with a unit vector in the given direction
 
LCKurtz said:
What you have calculated is the total differential of f(x,y), which includes both partials ##f_x## and ##f_y##. What is the formula for the directional derivative? Show us what happens when you try to calculate it.

hedipaldi said:
it is the dot product of the gradient at P with a unit vector in the given direction

You ignored the part I highlighted in red.
 
try to calculate what?don't you need to calculate the directional derivative?
 
hedipaldi said:
try to calculate what?don't you need to calculate the directional derivative?

Yes. You posted a question because you were apparently stuck on the problem. You have now stated that you need to take the gradient at P dotted into a unit vector. So please do it and show us what exactly you are stuck on.
 

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