Find H for Water Stream | V=155.8828 cm^3/g & 1000 kPa

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To determine the enthalpy (H) for a water stream with a specific volume of 155.8828 cm^3/g at 1000 kPa, using steam tables is essential. The discussion highlights the importance of knowing whether the water is superheated or saturated, which requires temperature data that is not provided. Participants suggest using the equation h=u+pv, but there is confusion about assuming internal energy (u) as zero. Ultimately, the specific volume must be compared to values in the steam tables to classify the state of the water and find the corresponding enthalpy values. Accurate interpretation of the steam tables is crucial for solving this problem effectively.
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Homework Statement


Determine H for a water stream with V=155.8828 cm^3/g at 1000 kPa.

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The Attempt at a Solution


I was thinking of using a steam table and finding the H from there, but it would have to be a water steam, not stream. Is there any other way of doing it? I feel like I'm missing something important, but it's just not coming to me.

Thanks in advance!
 
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If the question is talking about H, the implication is that you're going to be using the steam tables.
 
That's what I thought, but we aren't given temperature so how do we know if it's superheated or or super-saturated or what-not? It seems like there is a lot of missing information that you need to solve with the steam table. I was thinking of using the equation h=u+pv and assuming u=0 because it is a steady state function. Would that work?
 
ialan731 said:
That's what I thought, but we aren't given temperature so how do we know if it's superheated or or super-saturated or what-not? It seems like there is a lot of missing information that you need to solve with the steam table.
What more do you need? You have the specific volume and the pressure. That's enough.
I was thinking of using the equation h=u+pv and assuming u=0 because it is a steady state function. Would that work?
No. What could possibly make you think that you could just assume u = 0? What is a "steady state function?"

Chet
 
Here's a hint: I found it in the steam tables.

Chet
 
Is it directly from the table? Do we use pv=nRT to get t and then h from the table?
 
ialan731 said:
Is it directly from the table?
Yes, but two adjacent columns are involved.
Do we use pv=nRT to get t and then h from the table?
No.
 
It's late and I'm about to go to bed. So I have one more hint for you. I hope that this doesn't reveal too much: Saturated.

Chet
 
I don't know. I'm not getting what you're saying, and I've asked people. Can you post the number so that I can see where you got it from? I'm looking at the saturated table and I found where P is, but it doesn't coincide with the given v. How would you get h from there even if it did?
 
  • #10
ialan731 said:
I don't know. I'm not getting what you're saying, and I've asked people. Can you post the number so that I can see where you got it from? I'm looking at the saturated table and I found where P is, but it doesn't coincide with the given v. How would you get h from there even if it did?
From your saturated table, what did you get for the temperature? What does your table show for the specific volume of the saturated vapor? What does your table show for the specific volume of the saturated liquid? What is 155.8828 cc/g expressed in the same units as your saturated table?

Don't worry for now about getting the enthalpy of the stream. I'll get you there. There are a couple of steps in between.

Chet
 
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  • #11
Here is what I found in the steam tables at P = 10 Bars:

Temperature = 179.9 C
Specific volume of saturated liquid = 0.001127 m^3/kg
Specific volume of saturated liquid = 0.194 m^3/kg
Enthalpy of saturated liquid = 762.8 kJ/kg
Enthalpy of saturate vapor = 2278 kJ/kg

Nominal specific volume of your stream = 0.1558828 m^3/kg

Does your stream consist of (a) pure saturated liquid, (b) a mixture of saturated liquid and saturated vapor, or (c) pure saturated vapor?

Chet
 
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