Find Harmonic Function on Disk: U(x,y)=y+y^2

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Homework Help Overview

The original poster attempts to find a harmonic function U on the disk defined by x² + y² < 6, which satisfies the boundary condition U(x, y) = y + y² on the disk's boundary. The problem involves concepts from potential theory and partial differential equations, specifically the Laplace equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest using Cauchy's integral formula to relate boundary values to interior values. Others propose separation of variables and solving the Laplace equation in polar coordinates. There are questions regarding the boundary condition and the nature of the Laplacian in polar coordinates.

Discussion Status

Participants are exploring various methods to approach the problem, including integral formulas and separation of variables. There is an ongoing discussion about the correct form of the Laplacian in polar coordinates and the implications of the boundary conditions. No consensus has been reached yet.

Contextual Notes

Participants note the periodicity of the angle θ, indicating it is 2π periodic, which may be relevant for the solution's formulation. There is also mention of previous experience with similar problems, suggesting a shared understanding of the underlying concepts.

Tony11235
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I am to find a function U, harmonic on the disk [tex]x^2 + y^2 < 6[/tex] and satisfying
[tex]u(x, y) = y + y^2[/tex] on the disk's boundary. I am not sure where to start. Hints, help, anything?
 
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Use the integral formula.
 
I would think Cauchy's integral formual would be useful here: you have the value of a function on a boudry and want the value in the interior.
 
You are trying to solve the Laplace equation on a disk. Try separation of variables, then break it down to 2 ODE's. Here is a start for you..

You will probably need to solve the PDE in polar coordinates.

- harsh
 
harsh said:
You are trying to solve the Laplace equation on a disk. Try separation of variables, then break it down to 2 ODE's. Here is a start for you..
You will probably need to solve the PDE in polar coordinates.
- harsh
Then is [tex]u(\sqrt{6}, \theta) = \sqrt{6} \sin(\theta) + 6\sin^2(\theta)[/tex] a boundary condition?
 
Tony11235 said:
Then is [tex]u(\sqrt{6}, \theta) = \sqrt{6} \sin(\theta) + 6\sin^2(\theta)[/tex] a boundary condition?

Looks right. Make sure you solve the correct PDE, the laplacian in r,theta is not as simple as U_rr and U_theta*theta

- harsh
 
harsh said:
Looks right. Make sure you solve the correct PDE, the laplacian in r,theta is not as simple as U_rr and U_theta*theta
- harsh
I know. In an earlier problem I had to compute the laplacian in polar. Oh and one more thing, is there anything else I need to know about [tex]\theta[/tex]? Other than [tex]0 < \theta < 2\pi[/tex] ?
 
The theta condition that you are going to use, I believe, will be that theta is 2pi periodic.

- harsh
 

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