Find 'k' for x(t)=k is solution for diff eq

  • Thread starter mesa
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  • #1
mesa
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Homework Statement



Find the value of k for which the constant function x(t)=k is a solution of the differential equation 6t^5dx/dt+7x−4=0.

The Attempt at a Solution



I have tried this several ways but no luck, here is one of my attempts,

solve for dx/dt,

dx/dt = (4-7x)/6t^5

take the integral,

x(t) = (1/6t^5)(4x-7x^2/2)

and that doesn't help :P
I am sure as usual I am missing something straightforward but I don't see it.
 

Answers and Replies

  • #2
STEMucator
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You have ##x(t) = k## therefore ##x'(t) = 0##.

Plugging those in yields :

##(6t^5)(0) + 7k − 4= 0##

I'm sure that you got this now. It's the same concept as in your prior thread.
 
  • #3
mesa
Gold Member
673
25
You have ##x(t) = k## therefore ##x'(t) = 0##.

Plugging those in yields :

##(6t^5)(0) + 7k − 4= 0##

I'm sure that you got this now. It's the same concept as in your prior thread.

You know....
At least missing these types of things typically only happens once.

Thanks again!
 

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