Find log_x(4) as x-->1: Understanding the Limit of logx(4)

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Homework Help Overview

The discussion revolves around evaluating the limit of log_x(4) as x approaches 1. Participants explore the implications of substituting x with 1 and the continuity of the logarithmic function in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the challenges of directly substituting x=1 into the logarithmic function, noting that it leads to an undefined expression. Some suggest using a variable substitution to analyze the limit, while others explore the behavior of the function as x approaches 1 from both sides.

Discussion Status

The conversation is active, with participants sharing different approaches and questioning the assumptions underlying their reasoning. There is acknowledgment of the limit's non-existence based on the behavior of the function near x=1, but no consensus on a definitive method to evaluate the limit has been reached.

Contextual Notes

Participants mention constraints such as the lack of coverage of the generalized binomial formula and the implications of approaching the limit from the left and right, which complicates the evaluation of the limit.

strigner
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Homework Statement
Evaluate
lim x-->1 logx(4)


The attempt at a solution
I can't understand this because basically if you plug in 1 as x, log14 doesn't have a solution because 1 to the power of anything is just 1.
 
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So that is clearly not a continuous function. But you don't find a limit by "plugging in" a number. If y= logx(4), then 4= xy. I think what I would do is let h= x-1 so that 4= (1+h)y and the limit is as h goes to 0. Apply the generalized binomial formula to (1+ h)y
 
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Thanks for the response, now I remember that I'm not looking for the value at 1, so that makes sense now. But I'm not sure what to do with that binomial as we haven't covered binomial formula.

I tried thinking about it with RHS and LHS limits. If you're approaching 1 from the left then y is a large negative and if you are approaching from the right then y is a large positive number, therefore the limit at 1 does not exist. Does that make sense?
 


HallsofIvy, correct me if I'm off track, but I think your approach hides the dependence of the limit in this variable [tex]y[/tex], and since there is no simple way to evaluate the generalized series, I'm not sure where to turn.

My first thought was this:

[tex] \log_x {4} = \frac{\log 4}{\log x}[/tex]

(I used logs base 10; obviously [tex]\ln[/tex] would also do)
Then look at the limit of this expression from the right and left. Explorations with SAGE confirmed my suspicions about this.

If I've missed something obvious, please let me know.
 


So even with [tex] <br /> \log_x {4} = \frac{\log 4}{\log x}<br /> [/tex] it looks like the limit does not exist because when approaching 1 from the left the denominator is a very small negative number making the limit negative infinity and when approaching from the right the denominator is a very small positive number making the limit postiive infinity, therefore limit does not exist, is that correct?
 


Yes.
 


Actually that was my point. Using the generalized Binomial formula for (1+ h)y gives 1+ hy+ higher power terms in h. 4= 1+ hy+ higher power terms in h. Taking the limit as h goes to 0 gives 4= 1 no matter what y is: the limit does not exist.
 

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