Find a g=a+bx that is orthagonal to the constant function

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SUMMARY

The discussion focuses on finding a linear polynomial g(x) = a + bx that is orthogonal to the constant function f(x) = 1 within the real linear space C(1, e) using the defined inner product (f, g) = integral(1 to e)(logx)f(g)g(x)dx. The norm of the function f(x) = sqrt(x) has been calculated as ll f ll = 1/2sqrt(e^2 + 1). The solution for part (b) indicates that the polynomial can be expressed as b[x - (e^2 + 1)/4], but the user struggles to derive this result using the inner product definition.

PREREQUISITES
  • Understanding of inner product spaces and their properties
  • Familiarity with polynomial functions and their representations
  • Knowledge of integration techniques, particularly definite integrals
  • Basic understanding of orthogonality in the context of function spaces
NEXT STEPS
  • Study the properties of inner products in function spaces
  • Learn how to derive orthogonality conditions for polynomials
  • Explore integration techniques involving logarithmic functions
  • Practice solving problems related to norms of functions in C(1, e)
USEFUL FOR

Students studying advanced calculus, particularly those focusing on functional analysis and inner product spaces, as well as educators looking for examples of orthogonality in polynomial functions.

Cassi
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Homework Statement


In the real linear space C(1, e), define an inner product by the equation (f,g) = integral(1 to e)(logx)f(g)g(x)dx.
(a) If f(x)=sqrt(x), compute ll f ll (the norm of f)
(b) Find a linear polynomial g(x)=a+bx that is orthagonal to the constant function f(x)=1

Homework Equations



The Attempt at a Solution


I have solved part (a) and found that ll f ll = 1/2sqrt(e2+1) but I am having trouble with part B.

I see that the answer is b[x-(e2+1)/4] but I cannot get this answer. I know that (f, g) = 0 but I do not know how to solve this.
 
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Cassi said:
I know that (f, g) = 0 but I do not know how to solve this.
Did you apply the definition of the inner product to this equation? Then you can solve it and get conditions for a and b.
 

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