I've got an assesment task tommorow and one of the questions on the practice exam has got me stumped(adsbygoogle = window.adsbygoogle || []).push({});

The eqaution is y=21xe^(-.9x) - 12xe^(-.6x)

The question asks to show how the maximum can be

e^(0.3x) = 70-63x/40-24x

If differentiated it and taken out the common factors to get

21e^(-.9x)(-.9x + 1) - 12e^(-.6x)(-.6x + 1) = 0

but have no idea how to make it e^(0.3x) = 70-63x/40-24x

If any one could help i would really appreciate it

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# Find math maximum homework

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