Find the maximum speed of the mass on a spring.
The spring and mass are lying on a horizontal surface, with the spring being attached to both the wall and mass. The mass is 8kg and the spring constant is 784 N/m. The spring, at resting state, is 20cm (0.2m), but the spring is currently stretched to 25cm (.25m).
f (frequency) is 1.576 Hz (this I calculated, it was not given so it could be wrong.).
I found this EQ online for Vmax: fA = 2pi
f = frequency
A = amplitude
The Attempt at a Solution
I was think of using the above formula, but I don't know how to find the Amplitude.
I have taken AP Calculus AB, but the Physics course I am taking is non- calculus based, so please try not to explain in calculus terms.
I do know that the mass has the maximum velocity right when it passes the equilibrium point.
*wait, i just saw you can solve for A from the fA=2pi. But how does this formula work for a spring if I have all the variables for the formula?