Find \nabla x curl E: Solve Using Properties of Vector Calculus

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SUMMARY

The discussion focuses on solving the vector calculus expression \(\nabla \times (\nabla \times E)\) using properties of curl and divergence. Given the equations \(\nabla \times E = -\frac{1}{c} \frac{\partial H}{\partial t}\) and \(\nabla \cdot E = 0\), participants confirm that the time derivative can be taken outside the curl operation. The relationship \(\nabla \times (\nabla \times E) = \nabla (\nabla \cdot E) - \nabla^2 E\) is highlighted as a key simplification for further analysis.

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  • Understanding of vector calculus, specifically curl and divergence operations.
  • Familiarity with Maxwell's equations, particularly the relationships between electric field E and magnetic field H.
  • Knowledge of partial derivatives and their application in physics.
  • Basic proficiency in manipulating vector identities in three-dimensional space.
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  • Study the properties of curl and divergence in vector calculus.
  • Learn about Maxwell's equations and their implications in electromagnetism.
  • Explore vector identities, particularly \(\nabla \times (\nabla \times \mathbf{A})\) for any vector field A.
  • Investigate the application of partial derivatives in electromagnetic theory.
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Students and professionals in physics, particularly those focusing on electromagnetism, as well as mathematicians and engineers working with vector calculus in applied contexts.

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given curl E = -1/c*([tex]\partial[/tex]H/[tex]\partial[/tex]t)
div E = 0
div H = 0
curl H = 1/c*([tex]\partial[/tex]E/[tex]\partial[/tex]t), find

[tex]\nabla[/tex] x ([tex]\nabla[/tex] x E)

how do i take [tex]\nabla[/tex] x curl E? i tried to do it by determinants, but I'm not sure which values correspond to the i, j, and k. so my next assumption is that there is some property that i can take advantage of to solve the problem. please help. thanks.
 
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[tex] \nabla \times E = -\frac{1}{c} \frac{\partial H}{\partial t}[/tex]


you could do it directly
[tex] \nabla \times (\nabla \times E) <br /> =\nabla \times ( -\frac{1}{c} \frac{\partial H}{\partial t})<br /> =-\frac{1}{c}(\nabla \times \frac{\partial H}{\partial t})[/tex]

and i think it should be ok to take the time derivative outside the curl, though you may want to confirm that...
[tex] -\frac{1}{c}(\nabla \times \frac{\partial H}{\partial t})=-\frac{1}{c}\frac{\partial}{\partial t}(\nabla \times H)[/tex]

and it should follow, otherwise, if you know the original field you could make use of the equality
[tex] \nabla \times (\nabla \times E) <br /> =\nabla (\nabla \cdot E) - \nabla^2 E[/tex]

which should simplify with some of the other info
 
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