Find Orthonormal Basis of R3: u1,u2,u3

Click For Summary
SUMMARY

The discussion centers on finding an orthonormal basis for R3, specifically vectors u1, u2, and u3. The user has successfully calculated u1 as 1/(sqrt(14))[1, 2, 3] and u2 as 1/(sqrt(3))[1, 1, -1]. The challenge remains in determining u3, which requires finding a vector orthogonal to both u1 and u2, with the suggestion to use the cross product for this purpose.

PREREQUISITES
  • Understanding of orthonormal bases in linear algebra
  • Familiarity with vector operations, specifically cross products
  • Knowledge of normalization of vectors
  • Basic concepts of span in vector spaces
NEXT STEPS
  • Learn how to compute the cross product of two vectors in R3
  • Study the properties of orthonormal bases in higher dimensions
  • Explore the Gram-Schmidt process for generating orthonormal sets
  • Investigate applications of orthonormal bases in computer graphics and physics
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with vector spaces and require a solid understanding of orthonormal bases and their applications.

morsel
Messages
29
Reaction score
0

Homework Statement


Note: the vectors are column vectors, not row vectors. Latex is not working for me right now.

Find an orthonormal basis u1, u2, u3 of R3 such that
span(u1) =
span [1 2 3]

and

span(u1,u2) =
span { [1 2 3], [1 1 -1] }


Homework Equations





The Attempt at a Solution


Let v1=[1 2 3] and v2=[1 1 -1]
Then u1=1/(sqrt14)[1 2 3] and u2=1/(sqrt3)[1 1 -1]

But how do I get u3 without v3?

Thanks in advance!
 
Physics news on Phys.org
Find a vector that's orthogonal to both u1 and u2. A cross product would come in handy.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
3K
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K