(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The work done by an external force to move a -8.5μC charge from point A to point b is 15x10^-4 J. If the charge was started from rest and had 4.82x10^-4 J of kinetic energy when it reached point b, what must be the potential difference between a and b

2. Relevant equations

W(nonconservative)=ΔKE+ΔPE

V=ΔPE/Q

3. The attempt at a solution

15x10^-4 - 4.82x10^-4 J= .001 J (Work = ke f - ke i (0) + PE f (0) - PE i) So PE i would equal -.001 J.

Then v= -.001J/-8.5x10^-6 C = 119.7 Volts.

But the answer is supposed to be -119.7 volts?

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# Homework Help: Find potential difference of negative charged particle?

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