Find radius and interval of convergence

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Homework Help Overview

The discussion revolves around determining the radius and interval of convergence for the series Σ √n (x-1)^(n) from n=1 to infinity. The participants are exploring convergence tests, specifically the Ratio Test and the Root Test, to analyze the series.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using the Ratio Test and the Root Test, with one participant expressing difficulty in applying the Ratio Test due to an indeterminate form. Another participant suggests starting with the Root Test and raises a question about the limit of a derived expression as n approaches infinity.

Discussion Status

Guidance has been offered regarding the application of the tests, with one participant providing a hint about evaluating the limit as n approaches infinity. There is an ongoing exploration of how to manipulate the derived expressions to find the radius of convergence.

Contextual Notes

Participants are working within the constraints of homework rules, which may limit the extent of assistance provided. There is an emphasis on understanding the behavior of the series as n approaches infinity.

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Homework Statement




Σ √n X (x-1)^(n)
n=1


Homework Equations




Ratio Test

let the series Σ An be a series with positive terms and lim as n ---> infinity is an+1 / an = finite number

a.

the series converges if r < 1

b.

the series diverges if r > 1 or r is infinite

c.

the test is inconclusive if r = 1.

Root Test

http://ltcconline.net/greenl/courses/107/Series/ratio.htm

The Attempt at a Solution





So far I've tried the Ratio test (can't figure out how to not get an indeterminate form of anyhthing less than infinity multiplied by zero)

Then the root test, I'm not even sure where to begin once I divide the n's by n.

-travis
 
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1) First use root test.
2) Then use ratio test
 
[tex]\frac{\sqrt{n+1}|x-1|^{n+1}}{\sqrt{n}|x-1|^n}= \sqrt{\frac{n+1}{n}}|x-1|= \sqrt{1+ \frac{1}{n}}|x-1|[/tex]

What is the limit of that as n goes to infinity?
 
just to help out say the limit as n->inf is = X. (hint as HallsofIvy pointed out, with his answer, plug in inf into n and rationalize what happens to the function )

Then to find the radius of convergence by the ratio test, X<1
that implies that -1<X<1. The you need to get X with a coefficient 1, if not then divide both side.
 

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