Find Resistance Between A and B

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Homework Help Overview

The original poster is tasked with finding the input resistance between points A and B in a circuit. They initially consider Thevenin's theorem but express confusion due to the circuit being an open circuit with no voltage sources present. They also mention a specific resistor configuration involving a 4-ohm resistor.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore various methods, including Thevenin's theorem and Y-Delta transformations. There are attempts to apply Kirchhoff's laws and discussions about introducing a voltage source to calculate current and resistance.

Discussion Status

Some participants have provided guidance on using a voltage source to find the equivalent resistance, while others have shared their calculations. There is an ongoing exploration of different approaches, with no explicit consensus reached on the best method.

Contextual Notes

Participants are navigating the complexities of circuit analysis, including the implications of an open circuit and the specific resistor configurations involved. There is mention of potential misunderstandings regarding the application of Kirchhoff's laws and Thevenin's theorem.

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Homework Statement



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I have to find the input resistance; the resistance between A and B. I think it's Thevinin's theroem, however it is already an open circuit and there are no voltage sources and I can't combine the resistors to make an equivalent. So what do I doEdit: Am I suppose to remove the 4 ohm resistor connecting the two parallels, and find the equivalent resistance of those two and then add back the 4 as if it were in series?...so the final answer is 16/3 ohm? or is that wrong?
 
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Have you heard of a Y-Delta transform?
 
No I don't believe so.
 
Place a voltage source across A-B and calculate the current that it would supply. The equivalent resistance will be the voltage divided by the current.
 
Ok, I tried it like you suggested vela. Made 3 Kirchhoff loops, put in an imaginary voltage source 10V, calculated the current to be 3.5A, so R should be 10/3.5...
 
That's the same answer I got.
 
Sweet, thanks!
 
I tried doing the loop thing, I don't think I did it right. Can you explain it please?
 
What loop thing? You won't get the answer with Kirchoff's laws alone. Instead, use Thevinin's theorem, pretending that there's a voltage V between A and B.
 
  • #10
It would be better if you explain what you tried, so we can identify where you're having trouble. It's kind of hard to boil all of circuit analysis down to a forum post.
 
  • #11
Never mind I think I got it. I1=7A/2, R=10V/3.5A.
 

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