Find speed of object traveling up a ramp

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SUMMARY

The discussion focuses on calculating the speed of an object at the bottom of a ramp using principles of conservation of energy. The object ascends a ramp inclined at 30.0 degrees, reaching a height of 40.0 m. The gravitational acceleration is given as 10.0 m/s². The solution involves equating the kinetic energy at point A to the potential energy at point B, confirming that the object comes to a stop at the top of the ramp.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Basic knowledge of kinetic and potential energy equations
  • Familiarity with trigonometric functions, specifically cosine
  • Knowledge of gravitational acceleration (g = 10.0 m/s²)
NEXT STEPS
  • Study the derivation of kinetic energy (KE = 0.5 * m * v²)
  • Learn about potential energy (PE = m * g * h) calculations
  • Explore the application of trigonometric functions in physics problems
  • Investigate the effects of friction on energy conservation in ramp scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding energy conservation in mechanics, particularly in ramp-related motion problems.

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Homework Statement



An object approaches the bottom of a ramp, point A. It goes up the ramp and turns around at point B, which is 40.0 m above A. The ramp makes an angle of 30.0 degrees with the horizontal. What is the speed of the object at point A? Neglect friction.

Homework Equations



g=10.0 m/s (squared)


The Attempt at a Solution



I did 2cos(30)40
 
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I would use conservation of energy - assuming you read the question to say it has stopped at point B.
Write the kinetic energy of the object at the start of the ramp
At the top of the ramp all this ke is pe, write down the equation for PE.
 

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