Find the amount of stored energy in a mouse trap

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To determine the stored energy in a mouse trap, the focus should be on the spring mechanism rather than gravitational potential energy. The relevant formula for elastic potential energy in a spring is PE = 1/2 kx^2, where k is the spring constant and x is the distance the spring is compressed or stretched. To find k, a Newtonmeter can be used to measure the force exerted by the spring, and the distance x can be determined based on the movement of the trap's arm. Additionally, expressing potential energy in terms of the angle from equilibrium may provide a more natural approach, particularly using the torsional spring constant. Accurate measurements of these variables will yield the potential energy stored in the mouse trap.
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Hello, I'm trying to find the amount of stored energy in a mouse trap when it is set. I've read up on Potential energy.. but all I've found is gravitational, electrical, or elastic potential energy.. and that E = MGH .. but i don't have any height..

but if anyone can point me in the right direction , i'd be much appreciative.

Thanks!

--Val
 
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Have you got the actual trap to measure it? You could use:

Work done =Force x distance moved in direction of force

and then measure the force with a Newtonmeter and see how far you have to pull it back to set it.
Not very accurate, but close enough...
 
With a mouse trap (I assume you are talking about one of the standard mouse traps you can buy in a store), it's not "mgh" but "kx" that is important. The mouse trap arm, when released, is moved by a spring. If k is the spring constant (the amount of force necessary to contract the spring a unit distance) then the work done in moving the spring through a distance x is kx and that is the energy involved in releasing the spring.

Since you probably are not given "k", you will need to measure it as Adrian Baker said.
 
HallsofIvy said:
With a mouse trap (I assume you are talking about one of the standard mouse traps you can buy in a store), it's not "mgh" but "kx" that is important. The mouse trap arm, when released, is moved by a spring. If k is the spring constant (the amount of force necessary to contract the spring a unit distance) then the work done in moving the spring through a distance x is kx and that is the energy involved in releasing the spring.

Since you probably are not given "k", you will need to measure it as Adrian Baker said.

I'm sure HallsofIvy was in a hurry when that was typed, but what he actually meant was that the PE of a spring with spring constant k is

\frac{1}{2} kx^2

:)

Zz.
 
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Wouldn't it be more "natural" to express the potential energy in terms of the rotated angle from equilibrium?
 
Okay.. So I have to use the Newtonmeter to find out how much force the spring is pushing down on the bar.. that gives me the K right.. and then the X distance would be the distance the end of the bar goes ? would it be the distance in a semicircle.. or the distance from the spring loaded position directly to the unloaded position? if that makes any sense.. then i can go and use the PE = 1/2KX^2 correct??

i thank you all for your help. much appreciated.

--Val
 
ValiantKhan said:
Hello, I'm trying to find the amount of stored energy in a mouse trap when it is set. I've read up on Potential energy.. but all I've found is gravitational, electrical, or elastic potential energy.. and that E = MGH .. but i don't have any height..

but if anyone can point me in the right direction , i'd be much appreciative.

Thanks!

--Val

A mouse trap is basically a lever arm which has a tourque on it caused by the spring. The spring coil has a torsional constant. Multiply the tortional constant by the angle that the arm is moved through from equilibrium and you get the potential energy of the system. This treats the mouse trap as if the board is nailed to the floor (i.e. remains fixed).

Pete
 
torsional spring constant

arildno said:
Wouldn't it be more "natural" to express the potential energy in terms of the rotated angle from equilibrium?
Right. If the rotational (torsional) spring constant is k (units of torque per angle), then the potential energy of the spring (at an angle θ from equilibrium) would be:
\frac{1}{2} k\theta^2
However, the spring does not start off in equilibrium (the closed position of the mousetrap is not θ = 0). So you'd have to measure k, and figure out θ1 and θ2.

Interesting!
 
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