Find the Angular Acceleration, acceleration and friction force extered

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SUMMARY

The discussion focuses on calculating the angular acceleration (α), linear acceleration (a), and friction force (F) for a circular disk with a radius of 595 mm and mass of 16 kg, subjected to a force T of 41 N at an angle of 39°. The equations used include the sum of forces in the x and y directions (ƩFx and ƩFy) and the moment about the center of mass (ƩMG). The user initially faced challenges due to having three equations with five unknowns but resolved the problem by recognizing that the vertical acceleration (ay) is zero and applying the static friction equation F = μs * N.

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Homework Statement


The circular disk of 595-mm radius has a mass of 16 kg with centroidal radius of gyration = 500 mm and has a concentric circular groove of 220-mm radius cut into it. A steady force T is applied at an angle θ to a cord wrapped around the groove as shown. If T = 41 N, θ = 39°, μs = 0.23, and μk = 0.19, determine the angular acceleration α of the disk, the acceleration a of its mass center G, and the friction force F which the surface exerts on the disk. The angular acceleration α is positive if counterclockwise, negative if clockwise; the acceleration a is positive if to the right, negative if to the left; and the friction force F is positive if to the right, negative if to the left.

I have attached an image of the question

Homework Equations



rs is the smaller radius of 220 mm

rL is the larger radius of 595 mm

I = k2
m

The Attempt at a Solution



I started off by drawing a FBD of the circular disk, in which I included the forces of T, mg, N (normal force) and F (friction force)

ƩFx: max = Tcos(θ) - F

ƩFy: may = Tsin(θ) - mg + N

ƩMG: IGα = Trs - FrL

So, now I have three equations but 5 unknowns: ax, ay, F, N and α. How do I find the other two equations?

EDIT:

I've just realized that ay = 0. So, could I use F = u*N, where u would be the kinetic of static friction, as the fourth equation?
 

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Yeah, I jumped the gun a bit.

It looked more complicated than it was. I've solved it now. Thanks
 

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